Extremum, Increase and Decrease Sections – Min and max problem (closest point to the graph) – Exercise 2136 Post category:Extremum, Increase and Decrease Sections Post comments:0 Comments Exercise Find the point on the graph of the function f(x)=xf(x)=\sqrt{x}f(x)=x Closest to the point (4,0). Final Answer Show final answer (312,312)(3\frac{1}{2},\sqrt{3\frac{1}{2}})(321,321) Solution Coming soon… Share with Friends Read more articles Previous PostExtremum, Increase and Decrease Sections – Min and max problem (Maximum area) – Exercise 2169 Next PostExtremum, Increase and Decrease Sections – Calculate global Extremum Points – Exercise 2225 You Might Also Like Extremum, Increase and Decrease Sections – A polynomial – Exercise 6814 July 24, 2019 Extremum, Increase and Decrease sections – Extremum to a polynomial function in a closed interval – Exercise 6872 July 28, 2019 Extremum, Increase and Decrease Sections – A rational function – Exercise 6820 July 24, 2019 Extremum, Increase and Decrease sections – Extremum to a function with a third root in a closed interval – Exercise 6878 July 28, 2019 Extremum, Increase and Decrease Sections – A quotient of functions with ln – Exercise 6837 July 25, 2019 Extremum, Increase and Decrease sections – Min/Max problems (minimal surface area) – Exercise 6889 July 29, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Extremum, Increase and Decrease sections – Extremum to a polynomial function in a closed interval – Exercise 6872 July 28, 2019
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