Indefinite Integral – Quadratic polynomial in a root – Exercise 2021 Post category:Indefinite Integral Post comments:0 Comments Exercise Evaluate the integral ∫1−x2dx\int \sqrt{1-x^2} dx∫1−x2dx Final Answer Show final answer ∫1−x2dx=12(x1−x2+arcsinx)+c\int \sqrt{1-x^2} dx =\frac{1}{2}(x\sqrt{1-x^2}+\arcsin x)+c ∫1−x2dx=21(x1−x2+arcsinx)+c Solution Coming soon… Share with Friends Read more articles Previous PostIndefinite Integral – Quadratic polynomial in a root – Exercise 2033 Next PostIndefinite Integral – A root of x in arcsin function – Exercise 2006 You Might Also Like Indefinite Integral – A quotient of functions with roots – Exercise 6605 July 16, 2019 Indefinite Integral – A polynomial to the power of a fraction – Exercise 6384 July 7, 2019 Indefinite Integral – A quotient of functions with ln function – Exercise 5403 May 17, 2019 Indefinite Integral – A multiplication of polynomials – Exercise 6382 July 7, 2019 Indefinite Integral – A rational function – Exercise 6393 July 8, 2019 Indefinite Integral – A rational function – Exercise 6398 July 8, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
