Indefinite Integral – Irreducible polynomial in denominator – Exercise 1965 Post category:Indefinite Integral Post comments:0 Comments Exercise Evaluate the integral ∫2x−5x2−6x+18dx\int \frac{2x-5}{x^2-6x+18} dx∫x2−6x+182x−5dx Final Answer Show final answer ∫2x−5x2−6x+18dx=ln(x2−6x+18)+13arctan(13x−1)+c\int \frac{2x-5}{x^2-6x+18} dx =\ln (x^2-6x+18)+\frac{1}{3}\arctan (\frac{1}{3}x-1)+c ∫x2−6x+182x−5dx=ln(x2−6x+18)+31arctan(31x−1)+c Solution Coming soon… Share with Friends Read more articles Previous PostIndefinite Integral – A quotient of functions with a root and a third root – Exercise 1982 Next PostIndefinite Integral – A quotient of functions with cos and sin – Exercise 2250 You Might Also Like Indefinite Integral – A rational function – Exercise 6393 July 8, 2019 Indefinite Integral – A multiplication of polynomials – Exercise 6382 July 7, 2019 Indefinite Integral – A quotient of exponential functions – Exercise 6387 July 7, 2019 Indefinite Integral – A quotient of functions with ln function – Exercise 5403 May 17, 2019 Indefinite Integral – A quotient of functions with roots – Exercise 6605 July 16, 2019 Indefinite Integral – A polynomial to the power of a fraction – Exercise 6384 July 7, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
