Definite Integral – A polynomial on a symmetric interval – Exercise 1612 Post category:Definite Integral Post comments:0 Comments Exercise Evaluate the integral ∫−33(x7−3x3+6x)11dx\int_{-3}^3 {(x^7-3x^3+6x)}^{11} dx∫−33(x7−3x3+6x)11dx Final Answer Show final answer ∫−33(x7−3x3+6x)11dx=0\int_{-3}^3 {(x^7-3x^3+6x)}^{11} dx= 0∫−33(x7−3x3+6x)11dx=0 Solution Coming soon… Share with Friends Read more articles Previous PostDefinite Integral – Finding area to a function with a parameter – Exercise 2385 Next PostDefinite Integral – A quotient of functions on a finite interval – Exercise 1604 You Might Also Like Definite Integral – A rational function on a finite interval – Exercise 6403 July 8, 2019 Definite Integral – A rational function with absolute value on symmetric interval – Exercise 6601 July 16, 2019 Definite Integral – A quotient of functions on a finite interval – Exercise 6412 July 8, 2019 Definite integral – area computation of a bounded domain – Exercise 6615 July 20, 2019 Definite Integral – x in absolute value on a finite interval – Exercise 6434 July 8, 2019 Definite Integral – rational function in absolute value inside ln function on symmetric interval – Exercise 6442 July 8, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Definite Integral – A rational function with absolute value on symmetric interval – Exercise 6601 July 16, 2019
Definite Integral – rational function in absolute value inside ln function on symmetric interval – Exercise 6442 July 8, 2019
