Definite Integral – A quotient of functions on a finite interval – Exercise 1604 Post category:Definite Integral Post comments:0 Comments Exercise Evaluate the integral ∫141+xx2dx\int_1^4 \frac{1+\sqrt{x}}{x^2} dx∫14x21+xdx Final Answer Show final answer ∫141+xx2dx=134\int_1^4 \frac{1+\sqrt{x}}{x^2} dx = 1\frac{3}{4}∫14x21+xdx=143 Solution Coming soon… Share with Friends Read more articles Previous PostDefinite Integral – A polynomial on a symmetric interval – Exercise 1612 Next PostDefinite Integral – Finding area between 3 functions – Exercise 5371 You Might Also Like Definite integral – area computation of a bounded domain – Exercise 6615 July 20, 2019 Definite Integral – An exponential function on a finite interval – Exercise 6421 July 8, 2019 Definite Integral – A polynomial in absolute value on a finite interval – Exercise 6436 July 8, 2019 Definite Integral – Finding area between parabola, line and axis-x – Exercise 7024 August 21, 2019 Definite Integral – Finding area between 3 lines – Exercise 7020 August 21, 2019 Definite Integral – Finding area between two curves – Exercise 6615 July 16, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
