Definite Integral – A quotient of functions on a finite interval – Exercise 1604 Post category:Definite Integral Post comments:0 Comments Exercise Evaluate the integral \int_1^4 \frac{1+\sqrt{x}}{x^2} dx Final Answer Show final answer \int_1^4 \frac{1+\sqrt{x}}{x^2} dx = 1\frac{3}{4} Solution Coming soon… Share with Friends Read more articles Previous PostDefinite Integral – A polynomial on a symmetric interval – Exercise 1612 Next PostDefinite Integral – Finding area between 3 functions – Exercise 5371 You Might Also Like Definite Integral – Finding area between 2 polynomials – Exercise 7009 August 21, 2019 Definite Integral – A polynomial on a symmetric interval – Exercise 6409 July 8, 2019 Definite Integral – Finding area between a polynomial and a line – Exercise 6793 July 23, 2019 Definite Integral – A rational function with absolute value on symmetric interval – Exercise 6601 July 16, 2019 Definite Integral – A quotient of functions with a root on a finite interval – Exercise 6425 July 8, 2019 Definite Integral – Split function on finite interval – Exercise 6444 July 9, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Definite Integral – A rational function with absolute value on symmetric interval – Exercise 6601 July 16, 2019
Definite Integral – A quotient of functions with a root on a finite interval – Exercise 6425 July 8, 2019