Improper Integral – An exponential divided by a polynomial on an infinite interval – Exercise 1541

Exercise

Evaluate the integral

\int_{-\infty}^0 \frac{e^{\frac{1}{x}}}{x^2} dx

Final Answer


\int_{-\infty}^0 \frac{e^{\frac{1}{x}}}{x^2} dx=1

Solution

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