Improper Integral – A quotient of exponential functions on an infinite interval – Exercise 1527 Post category:Improper Integral Post comments:0 Comments Exercise Evaluate the integral ∫3∞e−3x9+e−3xdx\int_3^{\infty} \frac{e^{-3x}}{9+e^{-3x}} dx∫3∞9+e−3xe−3xdx Final Answer Show final answer ∫3∞e−3x9+e−3xdx=−13ln9+13ln(9+e−9)\int_3^{\infty} \frac{e^{-3x}}{9+e^{-3x}} dx=-\frac{1}{3}\ln 9+\frac{1}{3}\ln(9+e^{-9})∫3∞9+e−3xe−3xdx=−31ln9+31ln(9+e−9) Solution Coming soon… Share with Friends Read more articles Previous PostImproper Integral – A sum of exponential functions with 2 infinite integration limits – Exercise 1566 Next PostImproper Integral – An exponential divided by a polynomial on an infinite interval – Exercise 1541 You Might Also Like Improper Integral – A rational function on an infinite interval – Exercise 6954 August 12, 2019 Improper Integral – A multiplication of functions on an infinite interval – Exercise 6976 August 12, 2019 Improper Integral – A sum of exponential functions on an infinite interval – Exercise 6989 August 21, 2019 Improper Integral – An exponential function with infinite integration limits- Exercise 6961 August 12, 2019 Improper Integral – A multiplication of functions on an infinite interval – Exercise 6979 August 21, 2019 Improper Integral – A rational function on an infinite interval – Exercise 6952 August 12, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Improper Integral – A multiplication of functions on an infinite interval – Exercise 6976 August 12, 2019
Improper Integral – A sum of exponential functions on an infinite interval – Exercise 6989 August 21, 2019
Improper Integral – An exponential function with infinite integration limits- Exercise 6961 August 12, 2019
Improper Integral – A multiplication of functions on an infinite interval – Exercise 6979 August 21, 2019