Improper Integral – A quotient of exponential functions on an infinite interval – Exercise 1527 Post category:Improper Integral Post comments:0 Comments Exercise Evaluate the integral \int_3^{\infty} \frac{e^{-3x}}{9+e^{-3x}} dx Final Answer Show final answer \int_3^{\infty} \frac{e^{-3x}}{9+e^{-3x}} dx=-\frac{1}{3}\ln 9+\frac{1}{3}\ln(9+e^{-9}) Solution Coming soon… Share with Friends Read more articles Previous PostImproper Integral – A sum of exponential functions with 2 infinite integration limits – Exercise 1566 Next PostImproper Integral – An exponential divided by a polynomial on an infinite interval – Exercise 1541 You Might Also Like Improper Integral – An exponential function on an infinite interval – Exercise 6950 August 12, 2019 Improper Integral – A multiplication of functions on an infinite interval – Exercise 6979 August 21, 2019 Improper Integral – A multiplication of functions on an infinite interval – Exercise 6976 August 12, 2019 Improper Integral – A rational function on an infinite interval – Exercise 6954 August 12, 2019 Improper Integral – A rational function on an infinite interval – Exercise 6612 July 16, 2019 Improper Integral – A sum of exponential functions on an infinite interval – Exercise 6989 August 21, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Improper Integral – A multiplication of functions on an infinite interval – Exercise 6979 August 21, 2019
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Improper Integral – A sum of exponential functions on an infinite interval – Exercise 6989 August 21, 2019