Indefinite Integral – A rational function – Exercise 1487 Post category:Indefinite Integral Post comments:0 Comments Exercise Evaluate the integral ∫−2x4+4x2−11−x2dx\int \frac{-2x^4+4x^2-1}{1-x^2} dx∫1−x2−2x4+4x2−1dx Final Answer Show final answer ∫−2x4+4x2−11−x2dx=2x33−2x+12ln∣1−x∣−12ln∣1+x∣+c\int \frac{-2x^4+4x^2-1}{1-x^2} dx=2\frac{x^3}{3} -2x+\frac{1}{2}\ln|1-x| -\frac{1}{2}\ln|1+x|+c∫1−x2−2x4+4x2−1dx=23x3−2x+21ln∣1−x∣−21ln∣1+x∣+c Solution Coming soon… Share with Friends Read more articles Previous PostIndefinite Integral – ln(x) – Exercise 1910 Next PostIndefinite Integral – A rational function – Exercise 1406 You Might Also Like Indefinite Integral – A polynomial to the power of a fraction – Exercise 6384 July 7, 2019 Indefinite Integral – A rational function – Exercise 6398 July 8, 2019 Indefinite Integral – A quotient of functions with roots – Exercise 6605 July 16, 2019 Indefinite Integral – A rational function – Exercise 6393 July 8, 2019 Indefinite Integral – A quotient of exponential functions – Exercise 6387 July 7, 2019 Indefinite Integral – A multiplication of polynomials – Exercise 6382 July 7, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
