Indefinite Integral – A quotient of functions with a root – Exercise 1398 Post category:Indefinite Integral Post comments:0 Comments Exercise Evaluate the integral ∫xx+1dx\int \frac{x}{\sqrt{x+1}} dx∫x+1xdx Final Answer Show final answer ∫xx+1dx=23(x+1)32−2(x+1)12+c\int \frac{x}{\sqrt{x+1}} dx =\frac{2}{3} {(x+1)}^{\frac{3}{2}}-2{(x+1)}^{\frac{1}{2}} +c ∫x+1xdx=32(x+1)23−2(x+1)21+c Solution Coming soon… Share with Friends Read more articles Previous PostIndefinite Integral – A sum of exponential functions to the power of 2 – Exercise 1401 Next PostIndefinite Integral – A quotient of functions with a root – Exercise 1396 You Might Also Like Indefinite Integral – A rational function – Exercise 6393 July 8, 2019 Indefinite Integral – A polynomial to the power of a fraction – Exercise 6384 July 7, 2019 Indefinite Integral – A rational function – Exercise 6398 July 8, 2019 Indefinite Integral – A quotient of functions with roots – Exercise 6605 July 16, 2019 Indefinite Integral – A quotient of functions with ln function – Exercise 5403 May 17, 2019 Indefinite Integral – A quotient of exponential functions – Exercise 6387 July 7, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
