Indefinite Integral – A quotient of functions with a root – Exercise 1396 Post category:Indefinite Integral Post comments:0 Comments Exercise Evaluate the integral ∫xx+1−1dx\int \frac{x}{\sqrt{x+1}-1} dx∫x+1−1xdx Final Answer Show final answer ∫xx+1−1dx=23(x+1)32+x+c\int \frac{x}{\sqrt{x+1}-1} dx=\frac{2}{3}{(x+1)}^{\frac{3}{2}} +x+c∫x+1−1xdx=32(x+1)23+x+c Solution Coming soon… Share with Friends Read more articles Previous PostIndefinite Integral – A quotient of functions with a root – Exercise 1398 Next PostIndefinite Integral – A quotient of functions with roots – Exercise 1392 You Might Also Like Indefinite Integral – A quotient of functions with ln function – Exercise 5403 May 17, 2019 Indefinite Integral – A rational function – Exercise 6398 July 8, 2019 Indefinite Integral – A polynomial to the power of a fraction – Exercise 6384 July 7, 2019 Indefinite Integral – A rational function – Exercise 6393 July 8, 2019 Indefinite Integral – A quotient of functions with roots – Exercise 6605 July 16, 2019 Indefinite Integral – A multiplication of polynomials – Exercise 6382 July 7, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
