Proving Derivative Existence – A function with a polynomial and a square root – Exercise 1140 Post category:Proving Derivative Existence Post comments:0 Comments Exercise Given the function f(x) = \begin{cases} 2x^2, &\quad x\leq 1 \\ 2\sqrt{x}, &\quad x >1\\ \end{cases} Is it differentiable at point x=1? Final Answer Show final answer The function is not differentiable at x=1. Solution Coming soon… Share with Friends Read more articles Previous PostProving Derivative Existence – A polynomial function inside a square root – Exercise 1147 Next PostProving Derivative Existence – A function with parameters – Exercise 1132 You Might Also Like Proving Derivative Existence – A multiplication with sin function – Exercise 1094 December 10, 2018 Proving Derivative Existence – A multiplication with sin function – Exercise 1101 December 10, 2018 Proving Derivative Existence – A function with parameters – Exercise 1123 December 12, 2018 Proving Derivative Existence – A function with parameters – Exercise 1132 December 13, 2018 Proving Derivative Existence – A polynomial function inside a square root – Exercise 1147 December 13, 2018 Proving Derivative Existence – A polynomial and an exponential functions – Exercise 1150 December 13, 2018 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Proving Derivative Existence – A polynomial function inside a square root – Exercise 1147 December 13, 2018
Proving Derivative Existence – A polynomial and an exponential functions – Exercise 1150 December 13, 2018