Calculating Derivative – Computing nth derivative – Exercise 1084

Exercise

Given the following function:

f(x)=lnxf(x)=\ln x

Compute its nth derivative.

Final Answer


f(n)(x)=(1)n1(n1)!xnf^{(n)}(x)={(-1)}^{n-1}(n-1)! x^{-n}

Solution

We compute the first derivatives and try to find a pattern for the nth derivative.

Using Derivative formulas, we get the first derivative:

f(x)=1xf'(x)=\frac{1}{x}

We want to compute the second derivative. To do this, we derive the first derivative and get:

f(x)=1x2=x2f''(x)=-\frac{1}{x^2}=-x^{-2}

Now, we want to compute the third derivative. To do this, again, we derive the second derivative and get:

f(x)=2x3f'''(x)=2x^{-3}

Next, we want to compute the forth derivative. To do this, again, we derive the third derivative and get:

f(4)(x)=6x4f^{(4)}(x)=-6x^{-4}

Now we look at the derivatives of the function:

f(x)=1x=x1f'(x)=\frac{1}{x}=x^{-1}

f(x)=1x2=(1)x2f''(x)=-\frac{1}{x^2}=(-1)\cdot x^{-2}

f(x)=2x3=12x3f'''(x)=2x^{-3}=1\cdot 2 x^{-3}

f(4)(x)=(1)123x4f^{(4)}(x)=(-1)\cdot 1\cdot 2\cdot 3 x^{-4}

One can see the pattern of the derivatives of the function, so the n-derivative is

f(n)(x)=(1)n1(n1)!xnf^{(n)}(x)={(-1)}^{n-1}(n-1)! x^{-n}

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