Definite Integral – A rational function on a symmetric interval – Exercise 6423 Post category:Definite Integral Post comments:0 Comments Exercise Evaluate the integral \int_{-1}^1 \frac{1}{2x+3} dx Final Answer Show final answer \int_{-1}^1 \frac{1}{2x+3} dx=\frac{1}{2}\ln 5 Solution Coming soon… Share with Friends Read more articles Previous PostDefinite Integral – An exponential function on a finite interval – Exercise 6421 Next PostDefinite Integral – A quotient of functions with a root on a finite interval – Exercise 6415 You Might Also Like Definite Integral – Split function on finite interval – Exercise 6448 July 9, 2019 Definite Integral – A polynomial in absolute value on a finite interval – Exercise 6436 July 8, 2019 Definite Integral – An exponential function on a finite interval – Exercise 6421 July 8, 2019 Definite Integral – Finding area between a polynomial and a line – Exercise 7006 August 21, 2019 Definite Integral – rational function in absolute value inside ln function on symmetric interval – Exercise 6442 July 8, 2019 Definite Integral – A rational function with absolute value on symmetric interval – Exercise 6601 July 16, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Definite Integral – rational function in absolute value inside ln function on symmetric interval – Exercise 6442 July 8, 2019
Definite Integral – A rational function with absolute value on symmetric interval – Exercise 6601 July 16, 2019