Extremum, Increase and Decrease sections – Extremum to a polynomial function in an absolute value in a closed interval – Exercise 6918 Post category:Extremum, Increase and Decrease Sections Post comments:0 Comments Exercise Determine the absolute extrema for the following function f(x)=∣x2−3x+2∣f(x)=|x^2-3x+2|f(x)=∣x2−3x+2∣ On the closed interval [−10,10][-10,10][−10,10] Final Answer Show final answer max[−10,10]f(x)=132\max_{[-10,10]}f(x)=132[−10,10]maxf(x)=132 min[−10,10]f(x)=0\min_{[-10,10]}f(x)=0[−10,10]minf(x)=0 Solution Coming soon… Share with Friends Read more articles Previous PostExtremum, Increase and Decrease sections – Extremum to a polynomial function inside a square root in a closed interval – Exercise 6916 You Might Also Like Extremum, Increase and Decrease sections – Extremum to a polynomial function inside a square root in a closed interval – Exercise 6916 July 30, 2019 Extremum, Increase and Decrease sections – Min/Max problems (maximal slope) – Exercise 6893 July 29, 2019 Extremum, Increase and Decrease sections – Extremum to a function with a third root in a closed interval – Exercise 6878 July 28, 2019 Extremum, Increase and Decrease Sections – A polynomial – Exercise 6826 July 25, 2019 Extremum, Increase and Decrease sections – Min/Max problems (maximal area) – Exercise 6884 July 28, 2019 Extremum, Increase and Decrease sections – Min/Max problems (minimal surface area) – Exercise 6889 July 29, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Extremum, Increase and Decrease sections – Extremum to a polynomial function inside a square root in a closed interval – Exercise 6916 July 30, 2019
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