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Extremum, Increase and Decrease sections – Extremum to a polynomial function in a closed interval – Exercise 6913

Determine the absolute extrema for the following function

$f(x)=x^2-4x+6$

On the closed interval

$[-3,10]$

Final Answer

$\max_{[-3,10]}f(x)=66$

$\min_{[-3,10]}f(x)=2$

Coming soon…

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