Extremum, Increase and Decrease sections – Extremum to a polynomial function in a closed interval – Exercise 6872 Post category:Extremum, Increase and Decrease Sections Post comments:0 Comments Exercise Determine the absolute extrema for the following function f(x)=x3+3x2−72x+90f(x)=x^3+3x^2-72x+90f(x)=x3+3x2−72x+90 On the closed interval [−5,5][-5,5][−5,5] Final Answer Show final answer max[−5,5]f(x)=f(−5)=400\max_{[-5,5]}f(x)=f(-5)=400[−5,5]maxf(x)=f(−5)=400 min[−5,5]f(x)=f(4)=−86\min_{[-5,5]}f(x)=f(4)=-86[−5,5]minf(x)=f(4)=−86 Solution Coming soon… Share with Friends Read more articles Previous PostExtremum, Increase and Decrease Sections – A quotient of functions with ln – Exercise 6837 Next PostExtremum, Increase and Decrease sections – Extremum to a polynomial function in a closed interval – Exercise 6876 You Might Also Like Extremum, Increase and Decrease sections – Min/Max problems (maximal area) – Exercise 6884 July 28, 2019 Extremum, Increase and Decrease Sections – x multiplied by an exponential function – Exercise 6831 July 25, 2019 Extremum, Increase and Decrease sections – Extremum to a polynomial function in a closed interval – Exercise 6876 July 28, 2019 Extremum, Increase and Decrease sections – Extremum to an exponential function in a closed interval – Exercise 6911 July 29, 2019 Extremum, Increase and Decrease sections – Extremum to a function with a third root in a closed interval – Exercise 6878 July 28, 2019 Extremum, Increase and Decrease Sections – A multiplication with a third root – Exercise 6829 July 24, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
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