Definite Integral – A rational function with absolute value on symmetric interval – Exercise 6601 Post category:Definite Integral Post comments:0 Comments Exercise Evaluate the integral ∫−11x3+∣x3∣x2−4dx\int_{-1}^1 \frac{x^3+|x^3|}{x^2-4} dx∫−11x2−4x3+∣x3∣dx Final Answer Show final answer ∫−11x3+∣x3∣x2−4dx=1+4ln3−8ln2\int_{-1}^1 \frac{x^3+|x^3|}{x^2-4} dx=1+4\ln 3-8\ln 2∫−11x2−4x3+∣x3∣dx=1+4ln3−8ln2 Solution Coming soon… Share with Friends Read more articles Previous PostDefinite Integral – Split function on finite interval – Exercise 6448 Next PostDefinite Integral – Finding area between two curves – Exercise 6615 You Might Also Like Definite Integral – A polynomial on a symmetric interval – Exercise 6409 July 8, 2019 Definite Integral – Finding area between 2 polynomials – Exercise 7009 August 21, 2019 Definite Integral – Finding area between a polynomial and a line – Exercise 7006 August 21, 2019 Definite Integral – A rational function on a symmetric interval – Exercise 6423 July 8, 2019 Definite Integral – Finding area between 3 functions – Exercise 5371 May 15, 2019 Definite Integral – A quotient of functions on a finite interval – Exercise 6412 July 8, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
