Definite Integral – A rational function on a finite interval – Exercise 6403 Post category:Definite Integral Post comments:0 Comments Exercise Evaluate the integral ∫1211x(x+1)dx\int_{\frac{1}{2}}^1 \frac{1}{x(x+1)} dx∫211x(x+1)1dx Final Answer Show final answer ∫1211x(x+1)dx=ln32\int_{\frac{1}{2}}^1 \frac{1}{x(x+1)} dx=\ln\frac{3}{2}∫211x(x+1)1dx=ln23 Solution Coming soon… Share with Friends Read more articles Previous PostDefinite Integral – Finding area between two functions and an asymptote – Exercise 5492 Next PostDefinite Integral – A polynomial on a symmetric interval – Exercise 6409 You Might Also Like Definite Integral – Split function on finite interval – Exercise 6448 July 9, 2019 Definite Integral – A quotient of functions on a finite interval – Exercise 6412 July 8, 2019 Definite Integral – Finding area between 3 lines – Exercise 7020 August 21, 2019 Definite Integral – Finding area between parabola, line and axis-x – Exercise 7024 August 21, 2019 Definite Integral – A rational function with absolute value on symmetric interval – Exercise 6601 July 16, 2019 Definite Integral – Finding area between two functions and an asymptote – Exercise 5492 May 25, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Definite Integral – A rational function with absolute value on symmetric interval – Exercise 6601 July 16, 2019
