Gradient – Calculate scalar field gradient and direction – Exercise 4257 Post category:Gradient Post comments:0 Comments Exercise Calculate the gradient of the scalar field u=xyz At point (2,1,1) And calculate its direction at this point. Final Answer Show final answer \nabla u(2,1,1)=\vec{i}+2\vec{j}+2\vec{k} \hat{\nabla} u(2,1,1)=\frac{1}{3}\vec{i}+\frac{2}{3}\vec{j}+\frac{2}{3}\vec{k} Solution Coming soon… Share with Friends Read more articles Previous PostGradient – A scalar field of x multiplied by an exponential function – Exercise 4262 Next PostGradient – A scalar field with ln and a square root – Exercise 4254 You Might Also Like Gradient – A scalar field with ln and a square root – Exercise 4254 March 24, 2019 Gradient – A scalar field of x multiplied by an exponential function – Exercise 4262 March 24, 2019 Gradient – Calculate maximum direction – Exercise 4265 March 24, 2019 Gradient – Calculate points where a particular gradient is obtained – Exercise 4275 March 24, 2019 Gradient – Tangent Plane Equation – Exercise 4361 March 26, 2019 Gradient – Tangent Plane Equation – Exercise 4363 March 26, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ