Vectors – Calculate the scalar multiplication of vectors – Exercise 3564

Exercise

The vectors

a,b\vec{a},\vec{b}

Create a 120 degree angle. Given that

a=3,b=4|\vec{a}|=3, |\vec{b}|=4

Calculate

aa\vec{a}\cdot \vec{a}

ab\vec{a}\cdot \vec{b}

(a+a)2{(\vec{a}+ \vec{a})}^2

(3a+2b)(a+2b)(3\vec{a}+2\vec{b})(\vec{a}+2\vec{b})

Final Answer

aa=9\vec{a}\cdot \vec{a}=9

ab=6\vec{a}\cdot \vec{b}=-6

(a+a)2=13{(\vec{a}+ \vec{a})}^2=13

(3a+2b)(a+2b)=43(3\vec{a}+2\vec{b})(\vec{a}+2\vec{b})=43

Solution

Coming soon…

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