Riemann Sum – Exercise 2318 Post category:Riemann Sum Post comments:0 Comments Exercise Evaluate the limit limn→∞∑k=1n9k+3n3kn+2n2\lim_{n \rightarrow \infty}\sum_{k=1}^n \frac{9k+3n}{3kn+2n^2}n→∞limk=1∑n3kn+2n29k+3n Final Answer Show final answer limn→∞∑k=1n9k+3n3kn+2n2=3−ln5+ln2\lim_{n \rightarrow \infty}\sum_{k=1}^n \frac{9k+3n}{3kn+2n^2}=3-\ln 5+\ln 2n→∞limk=1∑n3kn+2n29k+3n=3−ln5+ln2 Solution Coming soon… Share with Friends Read more articles Previous PostRiemann Sum – Exercise 2322 Next PostRiemann Sum – Exercise 2311 You Might Also Like Riemann Sum – Exercise 2311 January 6, 2019 Riemann Sum – Exercise 2322 January 6, 2019 Riemann Sum – Exercise 2330 January 6, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
