Proving Derivative Existence – A function with parameters – Exercise 1132 Post category:Proving Derivative Existence Post comments:0 Comments Exercise Given the function (a and b parameters) f(x)={2x2,x≤2ax+b,x>2f(x) = \begin{cases} 2x^2, &\quad x\leq 2 \\ ax+b, &\quad x >2\\ \end{cases}f(x)={2x2,ax+b,x≤2x>2 For which values of the function parameters is it differentiable? Final Answer Show final answer a=8,b=−8a=8, b=-8a=8,b=−8 Solution Coming soon… Share with Friends Read more articles Previous PostProving Derivative Existence – A function with a polynomial and a square root – Exercise 1140 Next PostProving Derivative Existence – A function with parameters – Exercise 1123 You Might Also Like Proving Derivative Existence – A multiplication with sin function – Exercise 1094 December 10, 2018 Proving Derivative Existence – A multiplication with sin function – Exercise 1101 December 10, 2018 Proving Derivative Existence – A function with parameters – Exercise 1123 December 12, 2018 Proving Derivative Existence – A function with a polynomial and a square root – Exercise 1140 December 13, 2018 Proving Derivative Existence – A polynomial function inside a square root – Exercise 1147 December 13, 2018 Proving Derivative Existence – A polynomial and an exponential functions – Exercise 1150 December 13, 2018 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Proving Derivative Existence – A function with a polynomial and a square root – Exercise 1140 December 13, 2018
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