Proving Derivative Existence – A multiplication with sin function – Exercise 1094

Exercise

Given the function

f(x) = \begin{cases} x\sin(\frac{1}{x}), &\quad x\neq 0 \\ 0, &\quad x =0\\ \end{cases}

Is it differentiable?

Final Answer


The function is differentiable for all x except at point x = 0.

Solution

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